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3 years ago

Find the area of the following triangle: b= 20, c = 15 , A=46

Mathematics

1 answer:

ikadub [295]3 years ago

4 0

Answer:

a = 46

b = 20

c = 15

b+c ≤ a

20 + 15 ≤ 46

61 ≤ 46

Step-by-step explanation:

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Vesna [10]

Answer:

D is correct. $x^2-2x-4=0$

Step-by-step explanation:

We are given the root of the equation

$x=1+\pm \sqrt{5}$

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, $a=1+\sqrt{5} , b=1-\sqrt{5}$

Equation form would be $(x-1-\sqrt{5})(x-1+\sqrt{5})=0$

Now we simplify the above equation to get correct option.

$x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0$

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So, D is correct. $x^2-2x-4=0$

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