Which equation shows you how to find 16-9?

The function y = -x + 4 has to main of {0.3,6). What is its range?

Komok [63]

Answer:

i think it's A if I'm wrong then wow

4 0

3 years ago

The slope of the line whose equation is 5 x - 3 y = 4 is 5/3 4/5 -3/5

vlada-n [284]

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have:

$5x-3y=4\qquad|\text{subtract 5x from both sides}\\\\-3y=-5x+4\qquad|\text{divide both sides by (-3)}\\\\y=\dfrac{5}{3}x-\dfrac{4}{3}$

<h3>Answer: 5/3</h3>

3 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

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we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

The point (-3, -5) is on the graph of a function. Which equation must be true regarding the function?

vlabodo [156]

Answer:

F(-3) = -5

Step-by-step explanation:

I got it right on the test

8 0

2 years ago

4 – 15 ÷ (30 – 33) =

cupoosta [38]

Answer: 9

Step-by-step explanation:

We will use the Order of Operations to solve.

Given:

4 – 15 ÷ (30 – 33)

Subtract 33 from 30:

4 – 15 ÷ (– 3)

Divide -15 by -3:

4 + 5

Add 4 to 5:

9

7 0

2 years ago

Read 2 more answers