<u>konrad509</u> is correct its l and lll.
Answer:
84
Step-by-step explanation:
-- the greatest common factor of the 15, the 9, and the 24 is 3 .
-- the greatest common factor of the b⁴, the b⁵, and the b³ is b³.
-- the greatest common factor of the c³, the c², and the c¹, is c¹.
-- the greatest common factor of the d², the d¹, and the d³ is d¹.
-- SO, the greatest common factor of the whole thing is ( 3 b³ c d ) .
Can you factor that out of the big mess ?
Please try it.
You should get (3 b³cd) (5 bc²d - 3 b²c - 8 d²) .
Answer:
amplitude=5
Step-by-step explanation:
y=a sin x
amplitude =|a|
here a=-5
|a|=5
What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
