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Slav-nsk [51]
3 years ago
13

PLEASE HELP 20 POINTS!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0
Sure you do.

What is the x-intercept ? It's the point where the graph crosses the x-axis.
But y=0 at every point on the x-axis !  So the x-intercept is the point where

5x + 3(0) = k
5x = k
<u>x = 0.2 k</u>


Similarly ... What is the y-intercept ? It's the point where the graph crosses the
y-axis. But x=0 at every point on the y-axis !  So the y-intercept is the point where

5(0) + 3y = k
3y = k
<u>y = k/3</u>

The sum of the x- and y-intercepts is 32.5 .
0.2k + k/3 = 32.5
Multiply each side by 5 :
k + 5k/3 = 162.5
Multiply each side by 3 :
3k + 5k = 487.5
8k = 487.5
Divide each side by 8 :
<u>k = 60.9375 </u>

The x-intercept is (0.2k, 0) = the point (12.1875, 0) .

The y-intercept is (0, k/3) = the point (0, 20.3125) .

Those are the two points. Now it wants you to find the distance between them.
Do you remember how to find the distance between 2 points ?

Find the (difference of their x-values) and square it.
Find the (difference of their y-values) and square it.
Add the two squares together.
Take the square root of the sum.
That's the distance between the points.

(12.1875)² + (20.3125)² = the square of the distance.

If you don't get 23.688 for the distance, then check your arithmetic.

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Two angles are supplementary angles. One angle measures 58 degrees. The other angle measures 3n + 5 degrees. What is the value o
stepladder [879]

Answer:

39

Step-by-step explanation:

Angles are supplementary when they add up to 180.  So, we know the other angle that isn't 58 is 180-58=122.  Therefore, 122=3n+5\\3n=117\\n=39

5 0
3 years ago
HELPPPP FIND THE AREA
GuDViN [60]

you can just split the figure in 2 separate figures and them add the areas:

area rec. 1:

3m×3m= 9m²

area rec. 2:

3m× (2m+3m)

= 3m×5m

=15m²

total area:

9m²+15m²= 24m²

5 0
2 years ago
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Question :-
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\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
1 year ago
Solve for x. x+2/3=−1/6
Sphinxa [80]

Answer:-

x=-5/2

Step-by-step explanation:

x+2/3=-1/6

after cross-mutiplying,

6(x+2)=-3

6x+12=-3

6x=-3-12

6x=-15

x=-15/6

x=-5/2

hope this helps u!!

6 0
3 years ago
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100 POINTS HURRY
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Answer: is in the picture

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