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Archy [21]
3 years ago
6

2. How many real number solutions are there to the equation 0 =-3x2 + x - 4?

Mathematics
1 answer:
goblinko [34]3 years ago
7 0

For this case we have the following quadratic equation:

-3x ^ 2 + x-4 = 0

Where:

a = -3\\b = 1\\c = -4

By definition, the discriminant of a quadratic equation is given by:

d = b ^ 2-4 (a) (c)

We have to:

d> 0: Two different real roots

dTwo different complex roots

d = 0: Two equal real roots

Substituting the values we have:

d = 1 ^ 2-4 (-3) (- 4)\\d = 1-48\\d = -47

So, we have two different complex roots

Answer:

Two different complex roots

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Answer:

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