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nikklg [1K]
3 years ago
11

Given the function f(x)=(x+3)^2 and g(x)=3x+13 determine the x values of the point intersection

Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

Answer:

x = - 4, x = 1

Step-by-step explanation:

At the point of intersection

f(x) = g(x) , that is

(x + 3)² = 3x + 13 ← expand left side using FOIL

x² + 6x + 9 = 3x + 13 ( subtract 3x + 13 from both sides )

x² + 3x - 4 = 0 ← in standard form

(x + 4)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 1 = 0 ⇒ x = 1

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5 0
3 years ago
Find the points of intersection between x^2+y^2=45 and -3x+y=15​
MatroZZZ [7]

Step-by-step answer:

Given:

Circle C1: x^2+y^2 = 45

Line L1: -3x+y=15

Need to find the points of intersection.

Solution:

basically we need to solve for the roots of equations C1 and L1.

Here, we can use substitution of L1 into C1.

Rewrite L1 as : y=3x+15

substitute into C1:

x^2+(3x+15)^2 = 45

Expand

x^2 + 9x^2+90x+225 = 45

Rearrange terms:

10x^2+90x+180 = 0

Simplify

x^2+9x+18 = 0

Factor

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x=-6 or x=-3

Back-substitute x into L1 to calculate y:

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x=-3, y=3*x+15 = 3(-3) + 15 = 6 => (-3, 6)

Therefore the intersection points are (-6,-3) and (-3,6)

Check using equation C1:

(-6)^2+(-3)^2 = 36+9 = 45  ok

(-3)^2+(6)^2 = 9 + 36 = 45 ok

Check using equation L1:

Point (-6,-3) : y = 3x+15 = 3(-6) +15 = -3  ok

Point (-3,6) : y = 3x+15 = 3(-3)+15 = 6 ok.

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