Question

Bob shoots off a small rocket from the balcony of his apartment. The balcony is 30 ft above the ground and the rocket travels at 40 ft/second. When does it reach the highest point? What is the highest point? When does it hit the ground (seconds)?

Answer 1

From the calculations;

• The highest point above the ground is 112 feet
• The time taken to reach this height is 8 seconds

Equations of motion

The equations of motion are used in kinematics to obtain the various variables that has to do with motion.

In this case;

distance covered = 30 ft

initial velocity = 40 ft/second

Final velocity = 0 m/s at the maximum height

Hence;

v^2 = u^2 - 2gh

since v = 0

u^2 = 2gh

h = u^2/2g

h = (40)^2/2(9.8)

h = 82 feet

highest point above the ground = 82 feet + 30 feet = 112 feet

Now;

v = u - gt

since v = 0

u = gt

t = u/g

t = 40/9.8

t = 4 seconds

Time taken to hit the ground = 2(4 seconds) = 8 seconds

Learn more about kinematics:brainly.com/question/27126557