Question

What is the slope of the line that passes through the points (-3, 5) and (1, 7)?

Answer 1

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{7}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{7-5}{1-(-3)}\implies \cfrac{7-5}{1+3}\implies \cfrac{2}{4}\implies \cfrac{1}{2}$

Answer 2

Answer:

The slope the line that passes through the given points (-3, 5) and (1, 7) is 1/2. Hence first option is correct

Solution:

Given, two points are (-3, 5) and (1, 7)  

We have to find the slope of a line that passes through the above given two points.

We know that, slope of a line that pass through $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here, in our problem, $x_{1}=-3, y_{1}=5 \text { and } x_{2}=1, y_{2}=7$

Now, slope m $=\frac{7-5}{1-(-3)}=\frac{2}{1+3}=\frac{2}{4}=\frac{1}{2}$

Hence, the slope the line that passes through the given points is 1/2. So, first option is correct.