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vekshin1
3 years ago
14

Given that f(x)=2x/3 evaluate f^-1(6)

Mathematics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

9

Step-by-step explanation:

we know by definition that

f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}

so now we evaluate

f^{-1}(6)=\frac{3*6}{2}\\\\=3*3\\\\f^{-1}(6)=9

and if we want to do an extra step

f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6

which works.

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2. Which of the following is the equation of a circle with the radius of 1.5 and its center at (-3,2)?
Iteru [2.4K]
(x - xo)^2 + (y - yo)^2 = r^2

[x - (-3)]^2 + [y - (2)]^2 = (1.5)^2

(x+3)^2 + (y-2)^2 = 2.25

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8 0
3 years ago
Find the equation of a line parallel to y=-10x-5 passing through the coordinate (-3,5)
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we can use the point-line method:  y-y0=m(x-x0)
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Here
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4 0
3 years ago
You have a bag that contains 20 quarters, 20 dimes, and 15 nickels. When randomly selecting two coins with no replacement find t
iogann1982 [59]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Vinil7 [7]

Answer:

Step-by-step explanation:

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7 0
2 years ago
Mouza, Alreem, Latifa, Zayed and Mohammed are
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Answer:

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Hoped this help

7 0
2 years ago
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