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Pani-rosa [81]
3 years ago
10

Rewrite the equation y−2=−3/2(x+6) in standard form.

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

For this case we have that by definition, the standard form of the equation of the line is given by:

ax + by = c

We have the following equation:

y-2 = - \frac {3} {2} (x + 6)

We manipulate the equation algebraically:

y-2 = - \frac {3} {2} x- \frac {3 * 6} {2}\\y-2 = - \frac {3} {2} x \frac {18} {2}\\y-2 = - \frac {3} {2} x-9\\y-2 + 9 = - \frac {3} {2} x\\y-7 = - \frac {3} {2} x\\2 (y-7) = - 3x\\2y-14 = -3x\\3x + 2y = 14

Finally, the equation is:

3x + 2y = 14

Answer:

3x + 2y = 14

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Answer:

draw out a number line going from positive 8 to negative 8, on the number line look at -8 and go one number to the right adding positive 1 leaving you with -7

Step-by-step explanation:

5 0
3 years ago
What expression is equivalent to 2^-3/2^-5?​
mr_godi [17]
2^2 , or 4
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.

So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2

The new exponent is 2 because -3-(-5) is equal to 2.

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3 years ago
Bagels: six in a bag Apples: eight in a bag Cookies: twelve in a box Juice Boxes: nine in a box Find the least number of package
Rasek [7]

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6 0
4 years ago
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

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3 years ago
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Ymorist [56]

I have it please like me or whatever

8 0
3 years ago
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