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3 years ago

10

Rewrite the equation y−2=−3/2(x+6) in standard form.

1 answer:

navik [9.2K]3 years ago

3 0

For this case we have that by definition, the standard form of the equation of the line is given by:

$ax + by = c$

We have the following equation:

$y-2 = - \frac {3} {2} (x + 6)$

We manipulate the equation algebraically:

$y-2 = - \frac {3} {2} x- \frac {3 * 6} {2}\\y-2 = - \frac {3} {2} x \frac {18} {2}\\y-2 = - \frac {3} {2} x-9\\y-2 + 9 = - \frac {3} {2} x\\y-7 = - \frac {3} {2} x\\2 (y-7) = - 3x\\2y-14 = -3x\\3x + 2y = 14$

Finally, the equation is:

$3x + 2y = 14$

Answer:

$3x + 2y = 14$

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The graph of a system of equations with the same slope and the same y-intercepts will have no solutions.

Liula [17]

I think the correct answer from the choices listed above is option C. <span>The graph of a system of equations with the same slope and the same y-intercepts will never have no solutions. Rather, it has an infinite number of solutions since all points of the lines intersects.</span>

4 0

3 years ago

Find the equation of the tangent line to the curve (a lemniscate)

olya-2409 [2.1K]

Answer:

$m=\frac{9}{13}$ and $b=\frac{40}{13}$

Step-by-step explanation:

The equation of curve is

$2(x^2+y^2)^2=25(x^2-y^2)$

We need to find the equation of the tangent line to the curve at the point (-3, 1).

Differentiate with respect to x.

$2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})$

$4(x^2+y^2)(2x+2y\frac{dy}{dx})=25(2x-2y\frac{dy}{dx})$

The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

Substitute x=-3 and y=1 in the above equation.

$4((-3)^2+(1)^2)(2(-3)+2(1)\frac{dy}{dx})=25(2(-3)-2(1)\frac{dy}{dx})$

$40(-6+2\frac{dy}{dx})=25(-6-2\frac{dy}{dx})$

$-240+80\frac{dy}{dx})=-150-50\frac{dy}{dx}$

$80\frac{dy}{dx}+50\frac{dy}{dx}=-150+240$

$130\frac{dy}{dx}=90$

Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

$y=\frac{9}{13}(x)+\frac{27}{13}+1$

$y=\frac{9}{13}(x)+\frac{40}{13}$

Therefore, $m=\frac{9}{13}$ and $b=\frac{40}{13}$ .

5 0

3 years ago

If f(x) = 4x2 - 5x + 7 and g(x) = 3x2 - 2x + 8, find f(x) + g(x). A) 7x2 - 7x + 15 B) 7x4 - 7x2 + 15 C) 7x2 + 15 D) 12x4 - 8x3 +

lutik1710 [3]

Answer:

A) 7x^2-7x+15

Step-by-step explanation:

f(x) = 4x2 - 5x + 7,

g(x) = 3x2 - 2x + 8

f(x) +g(x) =

4x^2 - 5x + 7 + 3x^2 - 2x + 8=

7x^2-7x+15

8 0

3 years ago

Students in an art class cut colored paper into equal-sized squares. The paper measures 6 cm by 12 cm and they do not want to wa

solmaris [256]

The greatest possible side length is 24 square piece

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3 years ago

X+12/2x-5 - 3x-2/2x-5

BARSIC [14]

Answer:

the answer to this question is 3x-10

8 0

3 years ago

Read 2 more answers