3 years ago

Describe a real-world situation in which you might use the expression 50+2x

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Hope this helps you!

You might be interested in

What is 10 times as many as

Talja [164]

Answer:

To answer this question, more information needs to be disclosed.

3 0

3 years ago

There are currently 2,732 students enrolled at a local community college. The student population is projected to increase at a r

Juliette [100K]

What are the options? I think it is y=.04x +2732

5 0

3 years ago

Read 2 more answers

A tractor trailer weighs 80,000 pounds. Two tractor trailers come upon a bridge with a sign saying it can only handle 100 tons.

NikAS [45]

Two tractor trailers would weigh 160,000 pounds, which is equal to 80 tons. 100-80= 20 tons that are still available.

3 0

3 years ago

Read 2 more answers

4sinθ – 1 = - 3 for 0<θ< 360

EastWind [94]

Answer:

$\theta = 210^\circ$ or $\theta = 330^\circ$

Step-by-step explanation:

$4 \sin \theta - 1 = -3$

$4 \sin \theta = -2$

$\sin \theta = \dfrac{-2}{4}$

$\sin \theta = -0.5$

For sin θ = 0.5, the reference angle is θ = 30 deg.

$\sin 30^\circ = 0.5$

$\theta = 210^\circ$ or $\theta = 330^\circ$

7 0

3 years ago

You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5

Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : $E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}$

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = $\dfrac{1.645\times11.5}{\sqrt{20}}$

$\approx4.23$

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0

3 years ago