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3 years ago

What form is this equation written in? y-7=2(x-6)

Mathematics

1 answer:

Alexxx [7]3 years ago

7 0

Answer:

this is written in point slope form

Step-by-step explanation:

y-y1 = m(x-x1)

the slope is 2

and the point is (6,7)

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Write a linear function rule for the data in the table. x 0 1 2 3 4 y 3 1 –1 –3 –5

Dima020 [189]

Answer:

f(x) = –2x + 3

Step-by-step explanation:

7 0

3 years ago

A table costs Rs 720 to make. He sells it for Rs 920. What percentage of profit did he earn?

jenyasd209 [6]

Answer:

27 7/9%

Step-by-step explanation:

Take the selling price and subtract the cost

920 -720 = 200

Divide it by the cost

200/720

.27777777

Change to percent form

27.777777%

27 7/9%

3 0

3 years ago

Read 2 more answers

Find a potential function for F or determine that F is not conservative. (If F is not conservative, enter NOT CONSERVATIVE.) F =

xxMikexx [17]

For $F$ to be conservative, we need to have

$\dfrac{\partial f}{\partial x}=\cos z$

$\dfrac{\partial f}{\partial y}=10y$

$\dfrac{\partial f}{\partial z}=-x\sin z$

Integrate the first PDE with respect to $x$ :

$\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx+\int\cos z\,\mathrm dx\implies f(x,y,z)=x\cos z+g(y,z)$

Differentiate with respect to $y$ :

$\dfrac{\partial f}{\partial y}=10y=\dfrac{\partial g}{\partial y}\implies g(y,z)=5y^2+h(z)$

Now differentiate $f$ with respect to $z$ :

$\dfrac{\partial f}{\partial z}=-x\sin z=-x\sin z+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

So we have

$f(x,y,z)=x\cos z+5y^2+C$

so $F$ is indeed conservative.

8 0

3 years ago

Find the tan A and sin B exactly.

Rudik [331]

Answer:

B - tan A = 4/3, sin B = 3/5

Step-by-step explanation:

First, lets find the length of the third side

b = √15² - 12² = √225 - 144 = √81 = 9

Now, lets get Tan A and Sin B

Tan A = 12/9 = 4/3
Sin B = 9/15= 3/5

Correct option is B

5 0

3 years ago

What is the completely factored form of t4 − 16?

Mashcka [7]

we know that

A difference of squares problem can be factored as follows:

$a^{2}-b^{2} =(a+b)(a-b)$

in this problem we have

$t^{4}-16$

Applying difference of squares

$t^{4}-16=(t^{2}-4)( t^{2}+4)$

the term

$(t^{2}-4)=(t+2)(t-2)$

substitute

$(t^{2}-4)( t^{2}+4)=(t+2)(t-2)( t^{2}+4)$

therefore

the answer is

$(t+2)(t-2)( t^{2}+4)$

7 0

3 years ago