the answer is 7Г2÷2 (the first one)
Answer:
4
-20
-12
Step-by-step explanation:
g(4)
= 4(4)-12
= 16-12
= 4
g(-2)
=4(-2)-12
=-8-12
=-20
g(0)
=4(0)-12
=0-12
=-12
Answer:
We start with 0 + 40.
1. 0 + 40
2. 1 + 39
3. 2 + 38
4. 3 + 37
.....
keep going....
.....
19. 18 + 22
20. 19 + 21
21. 20 + 20
There are 21 pairs of whole numbers that have a sum of 40.
Step-by-step explanation:
hope this helps :)
To solve this we use the
equation,
<span> M1V1 = M2V2</span>
<span> where M1 is the
concentration of the stock solution, V1 is the volume of the stock solution, M2
is the concentration of the new solution and V2 is its volume.</span>
<span>
</span>
<span>M1 = .80 g H2SO4 / g solution (1018 g solution / L solution ) (1 mol / 98.08) = 8.30 M</span>
<span>
</span>
<span>8.30 (V1) = (5.0 M) (1.5 L)</span>
<span>V1 = 0.9036 L or 903.6 mL of the stock needed</span>
There isn’t a picture so I’m not sure how to answer
