Answer: Ground Speed = 91 km/hr, Bearing = 189°
<u>Step-by-step explanation:</u>
Step 1: Draw a picture (see attached) to determine the angle between the given vectors. Notice that I moved the wind vector 180° <em>so the head of the wind vector would line up with the tail of the plane vector. </em>This created an angle of 34° between the plane and wind vectors. <em>Why?</em>
- the dashed line is 45°
- 79° (plane) - 45° (wind) = 34°
Step 2: Solve for the length of the resultant vector using Law of Cosines
<em>c² = a² + b² - ab cos C</em>
c² = (111)² + (25)² - (111)(25) cos 34°
c² = 12,946 - 4601
c² = 8345
c = 91
Ground speed is 91 km/hr
Step 3: Solve for the bearing of the resultant vector using Law of Sines




A = 9°
<em>Reminder that we moved the wind vector 180° to create the resultant vector so we need to add 180° to our answer.</em>
Bearing = A + 180°
= 9° + 180°
= 189°
Answer:
The square is the next step
Step-by-step explanation:
Answer:
A. 15
Step-by-step explanation:
Hypotenuse = 22
Since the two angles other than the 90° are both
45° , it means that the two legs of the right triangle are of equal length.
So, (x)²+ (x)² = 22²
2x² = 22²
x² = 484/2
x² = 242
x = √242
x = 15.55
x ≈ 15
Divide numerator (top number) by denominator (bottom number). 3 divided by 8. It’s 0.375
From the side/angle inequality, we see that the smallest angle of a triangle must be opposite its shortest side. In this case, that angle is opposite the shortest side
so our answer is 
As for finding its measure (which I'm aware the question probably didn't ask for), we can use the law of cosines:

