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OLEGan [10]
3 years ago
12

Identify the domain of this function

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0

When you think of domain, you always think x-values. so the domain values for this graph is (-∞,∞).

Alex17521 [72]3 years ago
7 0

This is a graph of sine. Domain is equal the set of all real numbers:

D=\mathbb{R}=(-\infty,\ \infty)

The domain is x-y, for which there is a graph.

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In order to figure out who will go first in a game, your friend asks you to pick a number between 1 and 25. What are the possibl
siniylev [52]

Answer:

Step-by-step explanation:

The possible outcomes include 1, 2, 3, etc., up through 25.  This in itself is insufficient to specify who will go first.  There must be some further criteria.

Suppose each player chooses and announces a number from this set by writing it down on a scrap of paper which is placed face-down on the table.  The person who chooses the smaller number goes first.  Or, the person who chooses the larger number goes first.

8 0
3 years ago
Plzzzzz I need this answer
valentina_108 [34]

Answer:

the answer is the first one which is 3/32inch^3

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Can someone please help me with this question!!!
Elena-2011 [213]

Answer:

32

Step-by-step explanation:

x+102=4x+6

102=3x+6

96=3x

32=x

Hope this helps!!!

5 0
2 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
☺
Fittoniya [83]

Answer: 1  teashirt=7 L

               1 hat= 3L

Step-by-step explanation:

2 T shirts= 31 -  17

2 T shirts= 14

1 T shirt=14/2

1 T = 7 L

14L+ 1H=17 L

one hat = 17 - 14=3 L

8 0
3 years ago
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