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a_sh-v [17]
3 years ago
14

The Three Stooges (Larry, Moe, and Curly) and the four Marx Brothers (Chico, Harpo, Groucho, and Zeppo) are randomly assigned a

place in line. What is the probability the first three in line will be Moe, Larry, and Curly in that order?
Mathematics
1 answer:
Mrac [35]3 years ago
8 0

Answer:

\frac{1}{210}

Step-by-step explanation:

We can use the probability that one person will be assigned to one place.

For the first place in line, what is the probability that Moe will stand there?

\frac{1}{7} because there is 7 people and 1 of Moe.

Then, for the second place in line, what is the probability that Larry will stand there?

\frac{1}{6} because there are 6 people now and one of Larry.

Finally, for the third place in line, what is the probability that Curly will stand there?

\frac{1}{5} because there are 5 people now and one of Curly.

To find the probability that they'll stand in that order, we can multiply the probabilities together.

\frac{1}{7}*\frac{1}{6}*\frac{1}{5}=\frac{1}{210}

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As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

78 = 5x - 9 + 2x + 10

78 = 7x + 1

On subtracting 1 on booth side

78 - 1 = 7x +1 - 1

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On dividing both side by 7.

\frac{77}{7} =  \frac{7x}{7}

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Answer:

<em><u>f</u></em><em><u>(</u></em><em><u>x</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>6</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>2</u></em><em><u>0</u></em>

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