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svetlana [45]
3 years ago
7

Lowest common multiple of 14 and 22 what is it ahhhhhhhhhhhhhhh

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

154

Step-by-step explanation:

List the prime factors of both

14 = 2 × 7

22 = 2 × 11

2 is a common factor of both so is only included once.

The lowest common multiple = 2 × 7 × 11 = 154

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An employee produces 9/2 widgets in 1/6 hour. How many widgets does the employee produce per hour?
makvit [3.9K]

Answer:

27 widgets

Step-by-step explanation:

just basic multiplying if  im wrong :P

7 0
3 years ago
A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a
storchak [24]

Answer:  267.

Step-by-step explanation:

When there is no prior information for the population proportion, then the formula we use to find the sample size to estimate the confidence interval :

n=0.25(\dfrac{z^*}{E})^2 , where z* = Critical z-value and E + amrgin of error.

Let p = proportion of packages of ground beef sold at a particular store that have an actual fat content exceeding the fat content stated on the label.

Since , we have no prior information about p. so we use above formula

with E = 0.06 and critical value for 95% confidence =z* =1.96  [By z-table ] , we get

n=0.25(\dfrac{1.96}{0.06})^2=0.25(32.6666)^2\\\\=(0.25)(1067.111111)\\\\=266.777777778\approx267

Hence, the required sample size is 267.

7 0
3 years ago
Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
3 years ago
In a group of dogs and their owners, there are exactly 20 heads and 64 legs. How many dogs are in the group
Juliette [100K]

Answer:

If we assume that everyone in the group is an owner, we would have

20*2=40 legs.

64-40=24 legs

Therefore, we need 24 more legs.

These 24 additional legs can be made from the difference of legs between the owners and dogs.

In this case, dogs have 4-2=2 more legs than an owner.

24 ÷ 2 = 12.

There are 12 dogs in the group.

8 0
3 years ago
Yall help me out please :(
EleoNora [17]

Answer:

I'm lost I messed up how do I delete my answer...

6 0
3 years ago
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