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lisabon 2012 [21]
3 years ago
6

What's the nearest integer to 600

Mathematics
1 answer:
OLga [1]3 years ago
4 0

600 is an integer, so the nearest integer would be 600 itself.

The question might be asking for the nearest integer <em>under </em>600, so maybe try 599

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What’s the answer to this problem???
Snowcat [4.5K]
Rewrite the equation into slope intercept form:
8y = -5x+16

divide everything by 8 to get just y
y = -5/8x+2

 the slope = -5/8
8 0
3 years ago
B<br>8<br>7<br>Find the length of "e" to the<br>nearest tenth using the<br>Pythagorean Theorem.<br>​
weeeeeb [17]

Answer:

≈ 10.63

Step-by-step explanation:

Pythagorean Theorem... Possibly the most easy theory in math once you understood it.

Here's the formula.

AB would be the hypothenuse

BC would be the opposite

CA would be the Adjacent.

But let's not make it complicated though, the question is actually quite easy.

You are asked to find AB, the hypothenuse.

The hypothenuse would be C.

BC and CA would be A and B.

It doesn't matter where are you going to place the numbers.

So,  

= 113

Now we would have to square root 113 since  

is an irrational number, and the question asks you to round ro the nearest tenth.

=10.63014581

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Your answer would be 10.63

Hope this answer helped :)

5 0
2 years ago
Evaluate 3r³+5,when r=2
Elza [17]

Answer:

29  

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A pile of 15 boxes is 3 metres high. What is the depth of each box?
schepotkina [342]

Answer:

15 boxes=3m=300cm

1 box=300cm÷15

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5 0
3 years ago
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Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).
kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Finding the lengths of the segments

For AB

AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14

For BC

BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28

For CD

CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12

For DA

DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0
3 years ago
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