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<h3>I'm solving it using substitution method:-</h3><h3>7x+2y=3 {given}</h3><h3>=>7x=3-2y</h3><h3>=>x=(3-2y)/7-------(1)</h3><h3>x-3y=30 {given}</h3><h3>=>x=30+3y</h3><h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3><h3>=>3-2y=210+21y</h3><h3>=>3-210=21y+2y</h3><h3>=>-207=23y</h3><h3>=>y= -207/23= -9</h3><h3>putting the value of y on eqn(1):-</h3><h3>x=(3-2y)/7</h3><h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3><h2>Hence, x=3, y= -9</h2>✌️✌️❤️❤️
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