Answer:
B. No, the remainder is -50.
General Formulas and Concepts:
<u>Algebra I</u>
- Roots are when the polynomial are equal to 0
<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define</u>
Function f(x) = x³ - 10x² + 27x - 12
Divisor/Root (x + 1)
<u>Step 2: Synthetic Division</u>
<em>See Attachment.</em>
To determine whether a given root is an actual root, the remainder must equal 0. Since we have a remainder of -50, the given root is not a factor of the polynomial.
<em>Please excuse the bad handwriting. Hope this helped!</em>
Answer:
Step-by-step explanation:
The question is:
<em>"6" and "3" cancels out as well as the "x"s and "y"s. Shown below</em>:
Answer:
Below in bold
Step-by-step explanation:
The sequence is:
3, x, y, 18
If this is an A P then
x - 3 = y - x
2x - y = 3 (A) and
y - x = 18 - y
2y - x = 18 (B)
Multiply (A) by 2:
4x - 2y = 6 (C)
Adding B and C:
3x = 24
x = 8.
and
2y - 8 = 18
2y = 26
y = 13.
So x = 8 and y = 13.
b) ar + ar^2 = 6ar^3 where a = first term and r = common ratio
Divide by a:
r + r^2 = 6r^3
6r^3 - r^2 - r = 0
r(6r^2 - r - 1) = 0
r(3r + 1)(2r - 1) = 0
So the 2 possible values of r
= -1/3 and 1/2.
i) The common ratio is positive so it must be 1/2.
Second term ar = 8
1/2 a = 8
a = 16.
So the first 6 terms are:
16, 8, 4, 2, 1, 1/2.
Answer:
14 days
Step-by-step explanation:
Amount earned by gardener for each day worked = $60
Amount paid by gardener for each day when absent = $15
Total number of days = 20
Let the total number of days when the gardener was working = x
Then he was absent for (20 - x) days.
Total amount earned during this period = $750
Then, ![\[60x - 15(20-x) = 750\] ](https://tex.z-dn.net/?f=%5C%5B60x%20-%2015%2820-x%29%20%3D%20750%5C%5D%0A)
=> ![\[60x + 15x - 300 = 750\]](https://tex.z-dn.net/?f=%5C%5B60x%20%2B%2015x%20-%20300%20%3D%20750%5C%5D)
=> \[75x = 1050\]
=> x = 14
So the gardener worked for 14 days out of 20.
