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ololo11 [35]
2 years ago
15

What is 12tenths+9tenths=_tenths=_ones_tenths

Mathematics
1 answer:
MArishka [77]2 years ago
7 0
12/10 + 9/10 = 21/10

21/10 simplified is 2 1/10
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Write an equation in slope-intercept form (y = mx + b) , that perpendicular to y = 2x - 4 that passes through the point (3, - 3)
FromTheMoon [43]

Answer:

Step-by-step explanation:

perp. -1/2

y + 3 = -1/2(x - 3)

y + 6/2 = -1/2x + 3/2

y = -1/2x - 3/2

8 0
2 years ago
Anybody know the answer for this?
Ne4ueva [31]
A. 

You can subtract values that are being divided in Sin waves. 
6 0
3 years ago
A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of
Elis [28]

Answer:

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

\hat p=0.27 estimated proportion of arrests that were not prosecuted

p_o=0.31 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:  

Null hypothesis:p\geq 0.31  

Alternative hypothesis:p < 0.31  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

3 0
3 years ago
Help me please due in 20 minutes
Kamila [148]

Answer:

y=4

Step-by-step explanation:

4 0
2 years ago
Question 8 The product of – x2 + 5x – 1 and a monomial is 4x2 20x + 4. What is the monomial? ОА 4. B 4X С -4 -47​
Scrat [10]

Answer: -4

Step-by-step:

-x^2+5x-1 x _ = 4x^2-20x+4

4x^2-20x+4 / -x^2+5x-1

In the blank the answer would be -4 which is the monomial.

6 0
3 years ago
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