9514 1404 393
Answer:
E. 4x -180
Step-by-step explanation:
Angles QPB and RAP are corresponding, so congruent. Angles QPR and ARP are alternate interior angles, so congruent. Triangles BQP and PQR are isosceles, so angle PBQ ≅ angle QPB and angle RQP = 180-2x.
The total of angles RQP and RQC is angle PQC, an external angle to triangle PQB. We know the exterior angle is equal to the sum of the remote interior angles. That means ...
angle PQC = angle QPB +angle QBP
y +(180 -2x) = x + x
y = 4x -180 . . . . . . . . . . . subtract (180-2x) from both sides
Answer:
1+2i
Step-by-step explanation:
midpoint: (6 + -4)/2 + (-2 + 6)/2 i
= 1+2i
Answer:
1. Sine A = 3/5
2. Cos A = 4/5
3. Tan A = 3/4
4. Sine B = 4/5
5. Cos B = 3/5
6. Tan B = 4/3
Step-by-step explanation:
1. Determination of Sine A
Opposite = 3 in
Hypothenus = 5 in
Sine A =?
Sine A = opposite / Hypothenus
Sine A = 3/5
2. Determination of Cos A
Adjacent = 4 in
Hypothenus = 5 in
Cos A =?
Cos A = Adjacent / Hypothenus
Cos A = 4/5
3. Determination of Tan A
Opposite = 3 in
Adjacent = 4 in
Tan A =?
Tan A = opposite / Adjacent
Tan A = 3/4
4. Determination of Sine B
Opposite = 4 in
Hypothenus = 5 in
Sine B =?
Sine B = Opposite / Hypothenus
Sine B = 4/5
5. Determination of Cos B
Adjacent = 3 in
Hypothenus = 5 in
Cos B =?
Cos B = Adjacent / Hypothenus
Cos B = 3/5
6. Determination of Tan B
Opposite = 4 in
Adjacent = 3 in
Tan B =?
Tan B = opposite / Adjacent
Tan B = 4/3
54 degrees is the measure of its compliment since complentary angles add up to 90 degrees.
