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vredina [299]
3 years ago
7

How can you decide which variable to solve for first when you are solving a linear system by substitution

Mathematics
1 answer:
Helen [10]3 years ago
7 0
There are many factors, it is all a matter of preference, normally, you want to try to solve for the easiest one to get to
example

if y ou had

(x-3)^2+y=9
you would solve for y becuase it is less tricky

it is all a matter of preference
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Answer:

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3 years ago
What is lim x→-3 sqrt x^2-8
vitfil [10]

If the  -8 is under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\

OR

If the -8 is not under the square root, then...

\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

4 0
1 year ago
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