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Semmy [17]
3 years ago
7

Drag and drop the equation to correctly complete the sentence.

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

y= 2x - 11

Step-by-step explanation:

(-7 +1 )/ (2-5) = 2

y= 2x +b

-1 = 2* 5 + b

solve for b and you get -11 so the equation of the line is :

y = 2x -11

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the volume of a prism with equilateral triangular cross-section is 270cm^3 . If the length if the prism is 10 root 3 cm, what is
stepan [7]

Given:

The volume of a prism with equilateral triangular cross-section is 270cm³.

Length of the prism = 10\sqrt{3} cm

To find:

The length of the side of the equilateral triangular cross-section.

Solution:

Formulae used:

Area of an equilateral triangle is

Area=\dfrac{\sqrt{3}}{4}a^2

Where a is the side length of equilateral triangle.

Volume of prism is

V=Bh

Where, B is base area and h is the height of the triangular prism.

Cross section of the prism is an equilateral triangular so the base area of the prism is  \dfrac{\sqrt{3}}{4}a^2 sq. cm.

The volume of the prism is

V=\dfrac{\sqrt{3}}{4}a^2\times 10\sqrt{3}

270=\dfrac{10(3)}{4}a^2

270=\dfrac{30}{4}a^2

270=7.5a^2

Divide both sides by 7.5.

\dfrac{270}{7.5}=a^2

36=a^2

\pm \sqrt{36}=a

6=a

It takes only positive value because the side cannot be negative.

Therefore, the length of the side of the equilateral triangular cross-section is 6 cm.

5 0
3 years ago
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5 0
3 years ago
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10 points Help Me Please I will give brainiest I did too part​
nikklg [1K]

Answer:

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7 0
2 years ago
Which point lies on a circle with a radius of 5 units and center at P(6,1)?
ryzh [129]

Answer:

Option B. R(2,4)

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

(x-6)^{2}+(y-1)^{2}=5^{2}

(x-6)^{2}+(y-1)^{2}=25

step 2

Verify each case

case A) Q(1, 11)

substitute the value of x=1, y=11 in the equation of the circle and then compare the results

(1-6)^{2}+(11-1)^{2}=25

25+100=25 ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) R(2,4)

substitute the value of x=2, y=4 in the equation of the circle and then compare the results

(2-6)^{2}+(4-1)^{2}=25

16+9=25 ------> is true

therefore

the ordered pair R lie on the circle

case C) S(4,-4)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(4-6)^{2}+(-4-1)^{2}=25

4+25=25 ------> is not true

therefore

the ordered pair S not lie on the circle

case D) T(9,-2)

substitute the value of x=4, y=-4 in the equation of the circle and then compare the results

(9-6)^{2}+(-2-1)^{2}=25

9+9=25 ------> is not true

therefore

the ordered pair T not lie on the circle

7 0
3 years ago
While driving past stores, Tatum counted the number of cars in the parking lots.
Vlad [161]

Answer:

9

Step-by-step explanation:

1, 3, 5, 9, 15, 19, 19

7 0
3 years ago
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