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sasho [114]
2 years ago
15

Help please and can somebody explain the angels as well

Mathematics
1 answer:
Readme [11.4K]2 years ago
3 0

Answer:

alternate exterior

Step-by-step explanation:

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What is f(x)= 2/3 x + 7
Eva8 [605]

Answer:

14x/3

its the correct ans

7 0
2 years ago
I give 20! Find the surface area. And without explanation please, I don’t have enough time.
oee [108]

Answer:

816 cm²

Step-by-step explanation:

Surface area of the composite figure = (surface area of the larger rectangular prism + surface area of the smaller rectangular prism) - area of the side of the smaller rectangular prism that is joined to the bigger prism.

✔️Surface area of the larger rectangular prism:

Area = L*W*H = 20*5*6 = 600 cm²

✔️surface area of the smaller rectangular prism:

Area = L*W*H = 12*4*6 = 288 cm²

✔️area of the side of the smaller rectangular prism that is joined to the bigger prism.

Area = L*W = 12*6 = 72 cm²

Surface area of the composite = (600 + 288) - 72 = 888 - 72 = 816 cm².

8 0
2 years ago
Question 3: Choose the correct unit*
algol13
The answer for your question is Option C. Kilometers
6 0
3 years ago
Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).
Firdavs [7]

Answer:

A) Particular solution:

2x+\frac{1}{2}e^{-x}-\frac{8}{5}

B) Homogeneous solution:

y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))

C) The most general solution is

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

Step-by-step explanation:

Given non homogeneous ODE is

y''+4y'+5y=10x+e^{-x}---(1)

To find homogeneous solution:

D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)

To find particular solution:

y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\

Substituting y_{p},y'_{p},y''_{p} in (1)

y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\

Equating the coefficients

5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\

The general solution is

y=y_{h}+y_{p}

from (2) ad (3)

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

6 0
2 years ago
Brian flips a fair coin 3 times. What is the probability of getting exactly 1 tail?
Leya [2.2K]

Answer:

1/3

Step-by-step

he flips the coin three time and there is one side so 1/3

3 0
3 years ago
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