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Softa [21]
3 years ago
8

Write a rule for determining the sign of the product when multiplying a positive and a negative integer

Mathematics
2 answers:
Flura [38]3 years ago
5 0

1 Negative+ 1 Negative  = A positive

1 negative + 1 positive =  A negative

1 positive + 1 positive  = A positive

Hope this helped :)

elena-14-01-66 [18.8K]3 years ago
5 0

think of it as this:

two of the same signs are posative

two different signs are negative

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Answer:

the answer would be:

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Step-by-step explanation:

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Breanna wrote a number that is 4 units from 0 on the number line.
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The cost to print digital photos at a local store is
snow_tiger [21]
<h2>The cost is same for both the options if we purchase 27 photos</h2>

Step-by-step explanation:

   Cost of a photo at a local store is $0.25 per photo. This cost can be modeled to be linear in number of photos as C_{1}(x)=0.25x.

   Cost of photos purchased online is $0.15 per photo. However there is a shipping cost of $2.70. This can also be modeled to be linear in number of photos as C_{2}(x)=2.70+0.15x.

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3 years ago
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Solve the equation cos (x/2) = cos x + 1. what are the solutions on the interval 0° ≤ x &lt; 360°?
Sedbober [7]

Answer:

Step-by-step explanation:

cos (x/2)=cos x+1

cos (x/2)=2cos ²(x/2)

2 cos²(x/2)-cos (x/2)=0

cos (x/2)[2 cos (x/2)-1]=0

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x/2=2nπ+π/2,2nπ+3π/2

x=4nπ+π,4nπ+3π

n=0,1,2,...

x=π,3π

or x=180°,540°,...

180°∈[0,360]

so x=180°

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2cos(x/2)-1=0

cos (x/2)=1/2=cos60,cos (360-60)=cos 60,cos 300=cos (360n+60),cos (360n+300)

x/2=360n+60,360n+300

x=720n+120,720n+300

n=0,1,2,...

x=120,300,840,1020,...

only 120° and 300° ∈[0,360°]

Hence x=120°,180°,300°

7 0
2 years ago
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