Answer:
Step-by-step explanation:
Given Equation:
x^3- 4x^2 + 2x+ 10 = x^2 - 5x-3
which simplifies to
x^3- 5x^2 + 7x+ 13 = 0
Given one of the roots is x = 3x+2i, the conjugate is therefore x = 3-2i.
The product is real, (x-3+2i)(x-3-2i) = x^2-6x+13
The other root can therefore be obtained by long division
(x^3- 5x^2 + 7x+ 13)/(x^2-6x+13) = x+1, or x=-1
Therefore the three roots are:
{x=3-2i, x=3+2i, x=-1 }
Answer:
x²+12x+11=(3x+21)
Step-by-step explanation:
x²+10x–11=(x–1) (+2x)
x²+12x–11=(3x–1) (+22)
x²+12x+11=(3x+21)
Hope that's what you're looking for
To find bigger number we have to investigate slowly our numbers. First numbers are the same, then is 4 vs 0. It makes that first number is greater and no matter whats next.
4. 4 4
4. 0 4 4
So
4.44>4.044
Answer:
5000x^8
Step-by-step explanation:
Converting from rectangular coordinates to polar coordinates involves setting
. Since the left hand side matches
perfectly, the equation's rectangular coordinate form is
.
