<h3>Further explanation</h3>
Given
3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,
Required
the new volume
Solution
Combined with Boyle's law and Gay Lussac's law
T₁ = 39 + 273 = 312
T₂ = 16 + 273 = 289
Input the value :
V₂ = (P₁V₁.T₂)/(P₂.T₁)
V₂ = (99 x 3000 x 289)/(45.5 x 312)
or we can write it as:
V₂ = 3000 L x (289/312) x (99/45.5)
Explanation:
C₄H₈O₂ C₂H₄O
C₄H₁₂O₄ CH₃O
C₂H₁₀O₂ CH₅O
The empirical formula is that which expresses the composition of a compound in the simplest whole number ratio of the atoms of the different elements that makes up a compound.
The molecular formula is the true formula of the compound. It expresses the actual number of moles of atoms of the different elements present in a molecule of the compound.
C₄H₈O₂ C₂H₄O
4: 8 : 2 divided by 2 gives 2: 4 : 1
C₄H₁₂O₄ CH₃O
4: 12: 4 divided by 3 gives 1: 3: 1
C₂H₁₀O₂ CH₅O
2: 10: 2 divided by 2 gives 1: 5: 1
learn more:
Empirical formula brainly.com/question/2774727
#learnwithBrainly
Answer:
There are 2.5 * 10^22 beryllium atoms in 0.37 grams
Explanation:
Step 1: Data given
The mass of an atom of beryllium is 1.5 x 10^-26 kg.
Total mass = 0.37 grams
Step 2: Calculate number of atoms
1 atom = 1.5 * 10 ^-26 kg
X atoms = 0.00037 kg
X = 0.00037/1.5*10^-26
X = 2.467 * 10^22 atoms ≈ 2.5 * 10^22 atoms
There are 2.5 * 10^22 beryllium atoms in 0.37 grams
Answer:
15.06 L
Explanation:
Using the ideal gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information provided in this question,
P = 3.50 atm
n = 1.9 moles
V = ?
T = 65°C = 65 + 273 = 338K
Using PV = nRT
V = nRT/P
V = (1.9 × 0.0821 × 338) ÷ (3.5)
V = 52.725 ÷ 3.5
V = 15.06 L
