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scoray [572]
4 years ago
11

17.0cm

Chemistry
1 answer:
Mademuasel [1]4 years ago
7 0

Answer:

24.68 g/cm³

Explanation:

We'll begin by calculating the volume of the marble. This can be obtained as follow:

Volume = 17 × 23 × 4

Volume = 1564 cm³

Next, we shall convert the mass of the marble (i.e 38.6 kg) to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

38.6 kg = 38.6 kg × 1000 g / 1 kg

38.6 kg = 38600 g

Therefore, 38.6 kg mass of the marble slab is equivalent to 38600 g.

Finally, we shall determine the density of the marble slab as follow:

Volume = 1564 cm³

Mass = 38600 g.

Density =..?

Density = mass /volume

Density = 38600 g / 1564 cm³

Density = 24.68 g/cm³

Therefore, the density of the marble slab is 24.68 g/cm³

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If a balloon containing 3000 L of gas at 39°C and 99 kPa rises to an altitude where the pressure is 45.5 kPa and the temperature
ludmilkaskok [199]

\tt =3000~L\times \dfrac{289}{312}\times \dfrac{99}{45.5}

<h3>Further explanation</h3>

Given

3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,

Required

the new volume

Solution

Combined with Boyle's law and Gay Lussac's law  

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

T₁ = 39 + 273 = 312

T₂ = 16 + 273 = 289

Input the value :

V₂ = (P₁V₁.T₂)/(P₂.T₁)

V₂ = (99 x 3000 x 289)/(45.5 x 312)

or we can write it as:

V₂ = 3000 L x (289/312) x (99/45.5)

3 0
3 years ago
Match each molecular formula to the corresponding empirical formula.
lawyer [7]

Explanation:

C₄H₈O₂                      C₂H₄O

C₄H₁₂O₄                       CH₃O

C₂H₁₀O₂                      CH₅O

The empirical formula is that which expresses the composition of a compound in the simplest whole number ratio of the atoms of the different elements that makes up a compound.

The molecular formula is the true formula of the compound. It expresses the actual number of moles of atoms of the different elements present in a molecule of the compound.

C₄H₈O₂                      C₂H₄O

4: 8 : 2 divided by 2 gives 2: 4 : 1

C₄H₁₂O₄                       CH₃O

4: 12: 4  divided by 3 gives 1: 3: 1

C₂H₁₀O₂                      CH₅O

2: 10: 2 divided by 2 gives 1: 5: 1

learn more:

Empirical formula brainly.com/question/2774727

#learnwithBrainly

5 0
4 years ago
The mass of an atom of beryllium is 1.5 x 10^-26 kg. How many beryllium atoms are present in beryllium film of mass 0.37 g used
timama [110]

Answer:

There are 2.5 * 10^22 beryllium atoms in 0.37 grams

Explanation:

Step 1: Data given

The mass of an atom of beryllium is 1.5 x 10^-26 kg.

Total mass = 0.37 grams

Step 2: Calculate number of atoms

1 atom = 1.5 * 10 ^-26 kg

X atoms = 0.00037 kg

X = 0.00037/1.5*10^-26

X = 2.467 * 10^22 atoms ≈ 2.5 * 10^22 atoms

There are 2.5 * 10^22 beryllium atoms in 0.37 grams

8 0
3 years ago
4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the
bonufazy [111]

Answer:

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Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 3.50 atm

n = 1.9 moles

V = ?

T = 65°C = 65 + 273 = 338K

Using PV = nRT

V = nRT/P

V = (1.9 × 0.0821 × 338) ÷ (3.5)

V = 52.725 ÷ 3.5

V = 15.06 L

4 0
3 years ago
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Liula [17]

Answer is equal to 7.51 kJ

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4 0
2 years ago
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