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11Alexandr11 [23.1K]
4 years ago
8

Water is always made up of _____ part hydrogen to ______parts oxygen by mass.

Chemistry
2 answers:
IgorC [24]4 years ago
8 0
I believe it's two part hydrogen and one part oxygen (H20)
saw5 [17]4 years ago
7 0

The formula of water is H_{2}O. Thus, molar ratio is 2:1.

Thus,

n_{H}:n_{O}=2:1

Number of moles are related to mass and molar mass as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Molar mass of hydrogen is 1 g/mol and that of oxygen is 16 g/mol

\frac{n_{H}}{n_{O}}=\frac{2}{1}

Converting molar ratio into mass ratio as follows:

\frac{\frac{m_{H}}{M_{H}}}{\frac{m_{O}}{M_{O}}}=\frac{2}{1}

Also,\frac{m_{H\times M_{H}}}{m_{O}\times M_{O}}=\frac{2}{1}

Putting the values of molar mass,

\frac{m_{H\times 1 }}{m_{O}\times 16}=\frac{2}{1}

Thus,

\frac{m_{H}}{m_{O}}=\frac{16\times 2}{1}=\frac{32}{1}

Thus, water is always made up of 32 part hydrogen to 1 part oxygen by mass.


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Calculate the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water. The molar mass of C6
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The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.

<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
  • The molar concentration of a solution can be calculated by dividing the number of moles by its volume.

  • According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.

The number of moles = 469g ÷ 180.156g/mol = 2.6mol

Volume of water in litres = 82/1000 = 0.082L

Concentration of solution = 2.6mol ÷ 0.082L = 31.71M

Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.

Learn more about concentration at: brainly.com/question/202460

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