The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
- The molar concentration of a solution can be calculated by dividing the number of moles by its volume.
- According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.
The number of moles = 469g ÷ 180.156g/mol = 2.6mol
Volume of water in litres = 82/1000 = 0.082L
Concentration of solution = 2.6mol ÷ 0.082L = 31.71M
Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
Learn more about concentration at: brainly.com/question/202460
Answer:
Function A: +3
Function B: +2
y intercept is greater in Function B, the value is 16
Explanation:
Your solution steps look correct, but the answer was not completed. Given that QR = 33.8 and PQ = 57.6, and Q is the right angle, then tan P = opposite / adjacent = QR / PQ = 33.8 / 57.6 = 0.586.
Then tan P = 0.586
Angle P = tan^-1 (0.586) = 30.4 degrees.