Answer:
Explanation:
First, I plotted both the lines on the graph, then I graphed the inequality.<u> </u><em>Please check out image.</em> Looking at the image, we can tell that the graph matches with Graph-C. Hence, Option C is correct.
Hoped this helped!
D. bottom right
Frequency is added here and found out!?
P(t)=500(1+4t/(50+t^2 ))
P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2
by the quotient rule
500 (-4t^2 + 200)/(t^2 + 50)^2
Hence
P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6