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Vadim26 [7]
3 years ago
14

Malcolm bought dog-food bowls to give away as prizes at a dog-lovers event. The plastic bowls cost $6 each and the stainless ste

el bowls cost $10.50 each. Malcolm bought 7 plastic bowls and spent a total of $136.50 on the prizes.
How many stainless steel bowls did Malcolm buy?
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
4 0
He bought nine 9 stainless steel bowls...
Alborosie3 years ago
4 0
Alright! In order to solve this problem we first have to find out how much he spend on plastic bowls. To do that we multiply the amount of plastic bowls he bought by the price:

7$ x 6 = $42

Then we subtract this value from our total price:

136.50 - 42 = 94.50 (This is how much he spend on steel bowls)

Then we divide this value by the price of the steel bowls:

\frac{94.50}{10.50} = 9!

He bought 9 stainless steel bowls.
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pogonyaev
Y-1=2(x+3) just plug into the formula
6 0
2 years ago
S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

4 0
3 years ago
Simplify (5x^2 -3x+3) - (x^2+2x-1).
Natali [406]
Eliminate parenthesis by using the distribution property

= 5x² -3x +3 - x² - 2x +1

Group similar terms

= (5-1)*x² + (-3 -2)*x + (3+1)

Then sum everything:

= 4x² -5x +4





7 0
3 years ago
Read 2 more answers
How do the expressions 8+k2−6 and 8(k+2)−4k compare when k = 7?
Andreas93 [3]

Answer:

8+k2-6>8(k+2)-4k

Step-by-step explanation:

8+7×2-6 and 8(7+2)-4×7

8+14-16 and (56+16)-28

6 and 44

8 0
2 years ago
In Exercises 27 and 28, find the domain of the function
Natali5045456 [20]

                                             Question 27

The graph on question 27 indicates that there are three points with the locations such as:

  • (2, 6)
  • (4, 12)
  • (6, 18)

In other words, there are three points that lie on the graph with the x-values such as:

{(2, 6), (4, 12), (6, 18)}

We know that the domain includes the set of x-values.

Hence, the domain of the function is:

  • Domain: {2, 4, 6}

Since the points are not connected between them. In other words, there is not a continuous line.

Thus, the function represented on the graph has a discrete domain.

                                        Question 28

The graph on question 27 indicates that the line segment with the end-points (0, 25) and (7, 20).

Since there is a continuous line between the points from x = 0 to x = 7.

Thus, the domain of the line function is:

  • Domain: {0, 1, 2, 3, 4, 5, 6, 7}

As the line segment is a continuous line. Thus, the domain is continuous.

3 0
3 years ago
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