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3 years ago

Find the nth term on the sequence 30,27,24,21

Mathematics

2 answers:

ololo11 [35]3 years ago

6 0

The formula would be n= a1- 3

postnew [5]3 years ago

5 0

30,27,24,21,19,16,13,10,7,4,1,-2,-5,-8,-11,-14,-17,-20,-23,-26
just take away 3 from each number

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X + y = 152, 8.5x + 12y = 1,656 How many hats were sold?

Elodia [21]

Answer:

x = 48 and y = 104

Step-by-step explanation:

Given equations are:

$x+y = 152\\8.5x+12y=1656$

From equation 1:

$x = 152-y$

Putting the value of y in equation 2

$8.5(152-y)+12y = 1656\\1292-8.5y+12y = 1656\\3.5y+1292 = 1656\\3.5y = 1656-1292\\3.5y = 364\\\frac{3.5y}{3.5} = \frac{364}{3.5}\\y = 104$

Now we have to put the value of y in one of the equation to find the value of x

Putting y = 104 in the first equation

$x+y = 152\\x+ 104 = 152\\x = 152-104\\x = 48$

Hence,

The solution of the system of equations is x = 48 and y = 104

The value of variable which was assumed for number of hats, is the total number of hats.

6 0

3 years ago

Two radar stations 5.5 miles apart are tracking an airplane. The straight line distance

Vesnalui [34]

Answer:

19°

Step-by-step explanation:

I have attached an image showing this elevation.

From the image, let's first find the angle A by using cosine rule.

Thus;

8.1² = 5.5² + 13.1² - 2(5.5 × 13.1)cos A

65.61 = 30.25 + 171.61 - 144.1cos A

144.1cos A = 171.61 + 30.25 - 65.61

144.1cosA = 136.25

cosA = 136.25/144.1

cosA = 0.9455

A = cos^(-1) 0.9455

A = 19°

5 0

2 years ago

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$