Set it up like a regular equation. I used:
As you can see, however, I inserted the "less than" symbol rather than the equal sign because values greater than a certain value can also equal "x". Solve it like a normal equation and you will arrive at:
<u>
</u>
This means that, as long as x is greater than 45, "6x" will be greater than "3x+135". Thus, if you bring 46 students, the Science Center will cost less.
The value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
<h3>How to evaluate the expression?</h3>
The expression is given as:
3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two
Rewrite properly as:
[3² * 3⁻⁵]/[5⁻²]
Apply the negative exponent law of indices
So, we have
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]
Apply the exponent law of indices
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]
This gives
[3² * 3⁻⁵]/[5⁻²] = 25/27
Hence, the value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
Read more about expressions at:
brainly.com/question/723406
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The point where the lines intersect is the point that satisfies both equations.
It is (1, 5), selection C.
d) You have a <u>difference of squares</u>:
49y² - 9 = (7y)² - 3²
Recall the identity,
a² - b² = (a - b) (a + b)
So,
49y² - 9 = (7y - 3) (7y + 3)
e) Pull out the common factor 3 from each term:
3x² - 3x - 90 = 3 (x² - x - 30)
Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so
3x² - 3x - 90 = 3 (x + 5) (x - 6)
f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so
x² - 13x + 42 = (x - 7) (x - 6)
Answer:
(10,6)
Step-by-step explanation:
The equation you would use to solve this is (x1+x2/2 , y1+y2/2) so when you plug in the numbers you get this (6+14/2 , 3+9/2) which eventually simplifies into (10, 6)
