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3 years ago

Evaluate the function for the given values of x.

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

g(3) = 11

g(-3) = 16

g(-1) =3

Step-by-step explanation:

For g(3)

g(x)= x² +2

g(3) = 3² + 2

g(3) = 9+2

g(3) = 11

For g(-3)

g(x) = -3x + 7

g(-3) = -3(-3) + 7

g(-3) = 9 + 7

g(-3) = 16

For g(-1)

g(x) = x² + 2

g(-1) = (-1)² +2

g(-1) = 1+2

g(-1) =3

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aleksklad [387]

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2 years ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

Solve for x. Please look at the picture and answer it. Thank you.

Tatiana [17]

<h3>Answer :- </h3>

x = 24

<h3>Solution :- </h3>

2x + 42 = 90
2x = 90 - 42
2x = 48
x = 48/2
x = 24

<em>Hope</em><em> it</em><em> helps</em><em> </em><em>~</em>

7 0

2 years ago

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Print Version

san4es73 [151]

Answer:

$9450

Step-by-step explanation:

We will use compound interest formula:

$F=P(1+r)^t$

Where

F is future amount [what we want to figure out]

P is present amount [9000]

r is rate of interest [since we want for 6 months, the annual interest divided by 2 is r. So r = 10/2 = 5% or 0.05]

t is the time [ the time period is for 6 months so t = 1 since we already converted the interest rate to 6 month chunk]

Putting in formula, we get:

$F=P(1+r)^t\\F=9000(1+0.05)^1\\F=9000(1.05)\\F=9450$

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3 years ago

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ElenaW [278]

Answer:

It was reflected down and to the right I think.

Step-by-step explanation:

8 0

2 years ago

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