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Lisa [10]
3 years ago
9

Which answer describes the transformation of f(x)=log2(x−5)−2 from the parent function g(x)=log2x ? A) It is the graph of g(x) s

hifted 5 units left and 2 units down. B) It is the graph of g(x) shifted 5 units right and 2 units down. C) It is the graph of g(x) shifted 2 units right and 5 units down. D) It is the graph of g(x) shifted 2 units left and 5 units down.
Mathematics
1 answer:
damaskus [11]3 years ago
4 0

Answer:

It is the graph of g(x) shifted 5 units right and 2 units down.

Step-by-step explanation:

Given : f(x)=log_2(x−5)−2  

the parent function g(x)=log_2(x)

To get f(x) , 5 is subtracted from x

If we add any number with x  then we shift left

If we subtract any number from x  then we shift right

Here 5 is subtracted from x , so we shift 5 units right

Also -2  at the end

If we add any number at the end , then we shift up

if we subtract any number at the end , then we shift down

Here 2 is subtracted at the end , so we shift 2 units down

It is the graph of g(x) shifted 5 units right and 2 units down.

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Cerrena [4.2K]

Answer:

Variable A and variable B have a negative linear association.

Step-by-step explanation:

We are asked to find which best describes the association between variable A and variable B.

From the scatter plot we could clearly see that as the value of variable A are increasing the corresponding value of variable B is decreasing.

Also we could see that the points are linear.

Hence, the relationship that best describes variable A and variable B is:

Negative linear Association

8 0
3 years ago
Read 2 more answers
At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equatio
andriy [413]

The correct format of the question is

At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. P = 400 ( 1.2 )^ t Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?

(A) 291

(B) 691

(C) 1040

(D) 1440

Answer:

The increase in the population at the end of 2009 is 291 people

Step-by-step explanation:

We are given the equation as P = 400 ( 1.2 )^ t

where

P = No of People

t= No of Years

it is given that in the year 2006 the population is 400

this will only happen when we take t= 0

so for

Year    value of t

2006-    t = 0

2007-    t  = 1

2008-    t = 2

2009     t = 3

No of people in 2009 will be

P = 400(1.2)^3

     = 400*1.728

   P  = 691.2

Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691

Increase = P(2009) - P(2006)

               = 691 - 400

                = 291

The increase in the population at the end of 2009 is 291 people.

4 0
3 years ago
Anjali paid $8 for a salad. She now has<br> $37. With how much money did she start?
sleet_krkn [62]

Answer:

Below.

Step-by-step explanation:

37+8= 45

45-8=37

so 45.

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3 years ago
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Answer:

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4 0
3 years ago
What is the range of y = (x - 5)^2 – 1?
Setler79 [48]

1.  The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of (x-5)^2.

3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

8 0
3 years ago
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