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Mrrafil [7]
4 years ago
12

Find three consecutive natural numbers such that the difference of four times the third number and twice the first number is fiv

e times the second number
answer pls asap
Mathematics
1 answer:
PolarNik [594]4 years ago
3 0
Consecutive numbers are 1 apart
they are
n,n+1,n+2

so the diffference of 4 times (n+2) and twice (n) is 5 times (n+1)

4(n+2)-2n=5(n+1)
expand/distribute
4n+8-2n=5n+5
2n+8=5n+5
minus 2n both sides
8=3n+5
minus 5 both sides
3=3n
divide by 3
1=n
n+1=2
n+2=3

the numbers are 1,2,3
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Answer:

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