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xxTIMURxx [149]
3 years ago
3

What could the expression p+0.15p/2 represent including units

Mathematics
1 answer:
Fed [463]3 years ago
6 0
So the given is p + 0.15p/2. First, find the least common multiple as the denominator of the sum. That would be 2. Then, for each term, divide the lcm with the term's denominator and multiply it with the numerator. For example, for the term p, it would be (2÷1)*p = 2p. Hence the sum would be:

(2p + 0.15p)/2
(2.15p/2
1.075p

The final expression is 1.075p.
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Three years ago, Sherman was twice as old as Clive. If Clive’s present age is c, which expression represents Sherman’s present a
iogann1982 [59]
2(c-3)=s

because you have to subtract 3 years from sherman's age first, so you need the parentheses
7 0
3 years ago
5
Snowcat [4.5K]
F(1) = 2
f(2) = 3f(1) = 3(2) = 6
f(3) = 3f(2) = 3(6) = 18 (A)
5 0
2 years ago
Read 2 more answers
I NEED HALP CAN SOMEONE HELP ME QUICK!
dybincka [34]

Answer:

2 times 3 is 6 to the 2nd power is 36 - 5 to the second power is 25

36-25=11

Step-by-step explanation:

6 0
3 years ago
The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.54 minutes and a st
Minchanka [31]

Answer:

0.0323 = 3.23%. Is unusual

Step-by-step explanation:

Using the normal distribution we can find z value with the mean and standard deviation as follows. x is the value we want to know its probability

z = (x - mean)/standard deviation

z = (5-8.54)/1.91

z = -1.85

Using z tables for normal distribution, for z = 1.85, we have an area under the curve of 0.9677. Since we want to know the probability for 5 minutes or less, we have to substract from

p = 1- 0.9677

p = 0.0323

An event with a probability less than 5% is considered unusual.

8 0
4 years ago
In an ore, 9.8% of its total weight is metal. How many pounds of metal are in 1,950 lb of ore?
Fudgin [204]

Answer

Find out the  how many pounds of metal are in 1,950 lb of ore .

To proof

let us assume that the pounds of metal are in 1,950 lb of ore be x .

As given

In an ore, 9.8% of its total weight is metal.

ore weight = 1,950 lb

9.8% is written in the decimal form

= \frac{9.8}{100}

= 0.098

Than the equation becomes

x = 0.098 × 1950

x = 191.1 pounds

Therefore the 191.1 pounds of metal are in 1,950 lb of ore .

Hence proved



5 0
3 years ago
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