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Tju [1.3M]
3 years ago
15

Three years ago, Sherman was twice as old as Clive. If Clive’s present age is c, which expression represents Sherman’s present a

ge in terms of Clive’s age? 2c − 3 2c + 6 2(c − 3) 2c + 3
Mathematics
1 answer:
iogann1982 [59]3 years ago
7 0
2(c-3)=s

because you have to subtract 3 years from sherman's age first, so you need the parentheses
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The sum of the lengths of two opposite sides of the circumscribed quadrilateral is 12 cm, the length of a radius of the circle i
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60cm^2

Step-by-step explanation:

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where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.

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3 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

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3 years ago
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Svetlanka [38]

Answer:

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It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.

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