Answer:
Area = 22.3 m^2
Perimeter 27.4 m^2
Step-by-step explanation:
Perimeter = __ m
Area __ m^2
The area of the triangle is about 4.2,
The area of the square is 4,
The area of the semicircle is 14.1,
14.1 + 4.2 + 4 = 22.3
Area = 22.3 m^2
9.4 + 6 + 4 + 4 + 4 = 27.4
Perimeter = 27.4 m^2
Therefore the area of the shape is about 22.3 m^2 and the perimeter is about 27.4 m^2.
Your first step when subtracting integers is (d) subtract the numbers
<h3>How to determine the first step?</h3>
The operation is given as:
Subtraction operation
Assume that the operation is a simple expression that involves subtraction, such as:
a - b
The first step is to subtract the numbers
Hence, your first step when subtracting integers is (d) subtract the numbers
Read more about subtraction at:
brainly.com/question/17301989
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<span>Exactly 8*pi - 16
Approximately 9.132741229
For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So:
sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2)
Therefore the radius of the circle is 2*sqrt(2).
And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8
So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229</span>
