Answer:
It will leave the sprinkler at speed of 
Step-by-step explanation:
We have given internal diameter of the garden hose 
So radius 
So area 
Water in the hose has a speed of 4 ft/sec
So 
Number of holes n = 36
Diameter of each hole 
So radius 
So area 
From continuity equation



Answer:
Slope=0
Step-by-step explanation:
Answer: About 83915 grams
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I hope this helps you
2x^2-4x+7=0 a=2 b=-4 c= 7
disctirminant =b^2-4ac
disctirminant =(-4)^2-4.2.7
disctirminant = 16-56= -40
x=-b+square root of disctirminant ÷2a
x=4+2square root of (-10)/4
x=2+square root of (-10)/2
x'=4 -2 square root of (-10)/4
x'=2 -square root of (-10)/2