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geniusboy [140]
3 years ago
15

I need help on these two! Can annoying explain?

Mathematics
1 answer:
True [87]3 years ago
3 0

You are solving the two equations for x.

9.

r = 4 + 7x - sx

We need to solve for x. x is only found in the right side. First, just flip the sides to find x only in the left side.

4 + 7x - sx = r

We want all terms with x on the left side, and all terms without x on the right side. Now we subtract 4 from both sides.

7x - sx = r - 4

Factor x in left side.

x(7 - s) = r - 4

Divide both sides by 7 - s.

x = \dfrac{r - 4}{7 - s}

12.

3z + 8 = 12 + 3x - z

Since x is only in the right side, flip the sides.

12 + 3x - z = 3z + 8

We need to isolate x in the left side, so subtract 12 from both sides and add z to both sides.

3x = 3z + 8 - 12 + z

3x = 4z - 4

Divide both sides by 3.

x = \dfrac{4z - 4}{3}

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4 0
3 years ago
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on one day, 4 plumbers and 5 helpers earned $182. On another day, working the same number of hours and at the same rate of pay,
Elanso [62]
I hope this helps you



4plumbers +5helpers =182

5plumbers +6helpers =224



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25plumbers+30helpers =1120



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4.28+5helpers =182



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7 0
3 years ago
Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}
kompoz [17]

Answer:

The ordered pair (-2,\, -4) is indeed a solution to the system:

\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right..

Step-by-step explanation:

Consider a system of equations about variables x and y. An ordered pair (x_{0},\, y_{0}) (where x_{0} and y_{0} are constant) is a solution to that system if and only if all equations in that system hold after substituting in x = x_{0} and y = y_{0}.

For the system in this question, (-2,\, -4) would be a solution only if both equations in the system hold after replacing all x in equations of the system with (-2) and all y with (-4).

The \texttt{LHS} of the equation y = (1/2)\, x - 3 would become (-4). The \texttt{RHS} of that equation would become (1/2) \, (-2) - 3. The two sides are indeed equal.

Similarly, the \texttt{LHS} of the equation y = -2\, x - 8 would become (-4). The \texttt{RHS} of that equation would become (-2)\, (-2) - 8. The two sides are indeed equal.

Thus, x = (-2) and y = (-4) simultaneously satisfy both equations of the given system. Therefore, the ordered pair (-2,\, -4) would indeed be a solution to that system.

8 0
2 years ago
#3 Can someone please help me with these questions!!!!
rosijanka [135]

Answer:

Option A 90,68

m\angle 1=90^o

m\angle 2=68^o

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

m\angle 1=90^o ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

so

m\angle EAB=m\angle ECB=m\angle 2

In the right triangle EAB

m\angle EAB+22^o=90^o ----> by complementary angles in a right triangle

so

m\angle EAB=90^o-22^o=68^o

therefore

m\angle 2=68^o

7 0
3 years ago
Can somebody plz use the diagram at the bottom to answer question 10 (only if u know how to do this) thx sm!
jonny [76]

Answer:

isosceles: 2 angles are the same and 2 sides are the same. Equilateral have all the same sides and angles. Saclene have all dfferent angles and sides.

11) isosceles

12) equilateral

13) isosceles or scalene unclear

---------{NOTICE}----------

If you have any additional questions the best way to reach me is via discord

user: michaelsaltandpepper#0001

5 0
2 years ago
Read 2 more answers
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