Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
F^-1(x)=6+2x/5 is ur inverse
Find AC using Pythagorean theorem
6^2 + 8^2 = AC^2
36 + 64 = AC^2
100 = AC^2
10 = AC
6+8+10 = 24
24/60 = 2/5
10/x = 2/5
50 = 2x
25 = x
Answer:
y = √-1040/7
Step-by-step explanation:
The equation of a unit circle is expressed as;
x²+y² = 1
Given the coordinate of P = (-33/7, y)
Substitute the coordinate into the give expression and find y;
(-33/7)²+y² = 1
Expand
y² = 1-(-33/7)²
According to difference of two square
y² = (1+(-33/7))1-(-33/7))
y² = (1-33/7)(1+33/7)
y² = -26/7(40/7)
y² = -1040/49
y= √-1040/49
y = √-1040/√49
y = √-1040/7
Hence the value of y is y = √-1040/7
Answer:
D 5/3
Step-by-step explanation:
Secθ= Hypotenuse/Adjacent
Secθ=10/6
Simplify: 10/6 -->5/3
Ans: D 5/3
remember your six trigonometric functions:
Sinθ=Opp/Hyp -->Cscθ=Adj/Hyp
Cosθ=Adj/Hyp -->Secθ=Hyp/Adj
Tanθ=Opp/Adj-->Cotθ=Opp?Adj
It is basically the opposite of each other, don't forget when you are at the last step you simplify! never forget. Also working with square roots will be a bit tricky when converting to Csc/ Sec/ Cot. Just noting you that Square roots don't belong in denominators!
