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3 years ago

Describe what happens to the graph of y=3x + 4 when the slope is changed 1/3 one over three

Mathematics

1 answer:

kumpel [21]3 years ago

5 0

Answer:

see the explanation

The graph in the attached figure

Step-by-step explanation:

we have

$y=3x+4$

This is a linear equation (the graph is a line)

The y-intercept is the point (0,4) ---> value of y when the value of x is equal to zero)

The x-intercept is the point (-4/3,0) ---> value of x when the value of y is equal to zero)

The slope is m=3

If the slope is changed to m=1/3

we have

$y=(1/3)x+4$

This is a linear equation too (the graph is a line)

The y-intercept is the point (0,4) ---> is the same

The x-intercept is the point (-12,0) ---> the x-intercept is different

The slope is m=1/3

The second line becomes a lot less steep

Remember that the slope is the ratio between the rise and the run

In the first line the ratio rise/run is 4/1

In the second line the ratio rise/run is 1/3

see the attached figure to better understand the problem

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2 years ago

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2 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$