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jenyasd209 [6]
3 years ago
7

Consider the following mechanism for the formation of tert-butanol: (CH_3)_3CBr(aq) rightarrow (Ch_3)_3 C^+ (aq) + Br^- (aq) (CH

_3)_3 C^+ (aq) + OH^- (aq) rightarrow (CH_3)_3 COH(aq) Write the chemical equation of the overall reaction: Are there any intermediates in this mechanism? yes no If there are intermediates, write down their chemical formulas. Put a comma between each chemical formula, if there's more than one.
Chemistry
1 answer:
Sloan [31]3 years ago
4 0

Answer:

The mechanism is in the attached file. The reaction intermediates are the following: C4H8O, C4H9O

Explanation:

Terbutanol is a tertiary alcohol. It is one of the four isomers of butanol. It is a transparent liquid (or a colorless solid, depending on the temperature), with an odor similar to camphor. It is very soluble in water and ethanol.

The scheme shows a protonation of the double bond and the nucleophilic attack of the water to the carbocation, then it loses a proton and the terbutanol is formed.

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Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati
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Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{vap}}{T_b}

where,

\Delta S = change in entropy

\Delta H_{vap} = change in enthalpy of vaporization = 40.5 kJ/mol

T_b = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{vap}}{T_b}

\Delta S=\frac{40.5kJ/mol}{352K}

\Delta S=115J/mol.K

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What is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?
zubka84 [21]
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g 
H: 16.3% = 16.3 g 

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

C:  \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol

H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

C:  \dfrac{6.975}{6.975} = 1

H:  \dfrac{16.3}{6.975} \approx 2.3

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, t<span>hus, the minimum or empirical formula found for the compound will be:
</span>
\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark

I hope this helps. =)
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