NH3 is a molecule with a nitrogen atom in the middle surrounded by 3 hydrogen atoms bonded covalently. Nitrogen has 5 valence electrons so, it will form sigma bonds (sp3 hybrid orbitals) with each of the hydrogen atom. The remaining lone pair electrons will be situated above the atom. You ca look at this image I've pulled from Google.

5 0

3 years ago

How many moles are in 4561 g of C3H7OH?

d1i1m1o1n [39]

Answer: 76.017 moles

Explanation:

3 0

3 years ago

The unburned, unfiltered fuel parts that remain to be removed through the exhaust are called

Anna007 [38]

The answer to this is hydrocarbons

8 0

3 years ago

How many grams of barium chloride are produced when 1.25 x 1023 molecules of HCl reacts with barium?

sp2606 [1]

Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.

<h2>Balanced reaction</h2>

The balanced reaction is

2 HCl + Ba → BaCl₂ + H₂

<h2>Moles of HCl that react</h2>

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?

amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms

<u><em>amount of moles of HCl= 0.2075 moles</em></u>

Then, 0.2075 moles of HCl react.

<h2>Reaction stoichiometry</h2>

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole

<h2>Mass of barium chloride produced</h2>

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?

$amount of moles of BaCl_{2} =\frac{0.2075 moles of HCl x 1 mole of BaCl_{2} }{ 2moles of HCl}$

<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>

Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:

$0.10375 molesx\frac{208.24 grams}{1 mole} =21.6 grams$

Finally, the mass of barium chloride produced is 21.6 grams.

Learn more about:

Avogadro's Number

Reaction stoichiometry

7 0

3 years ago