Answer:
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It’s a combustion reaction but what are you trying to find?
The number of moles of aluminium that are needed to react completely with 13.2 moles of FeO is 8.8 moles
calculation
2Al + 3FeO → 3aFe +Al2O3
by use of of mole ratio of Al: FeO from equation above = 2:3 the moles of Al is therefore
= 13.2 x 2/3=8.8 moles of Al
2Agl + 1Na2S----->1 Ag2S + 2Nal
This may help