Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
27+3x-31=20
-4+3x=20
+4 +4
3x=24
X=8
Answer:
x = 5.5 (rounded)
Step-by-step explanation:
Equation: 700 = 132.69x - 25.96
Add 25.96 to both sides: 700+25.96 = 132.69x -25.96 + 25.96
Simplify: 725.96 = 132.69x
Isolate x
Divided both sides by 132.69: 
Simplify: x = 5.5 (rounded)
The elimination method is a sufficient way to solve problems.
2x+y= 20
6x-5y=12
Add 5y to the one equation.
2x+6y= 20
6x= 12
Subtract 2x from both sides.
6y= 20
4x= 12
Divide 6 by 20.
y= 3.3
Divide 4 by 12.
x= 3
I hope this helped you!
Brainliest answer is appreciated!
