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Fofino [41]
4 years ago
15

Estimate the value of: square root of 34

Mathematics
1 answer:
Georgia [21]4 years ago
5 0

Answer:

  d.  √34 ≈ 5.82

Step-by-step explanation:

Both of choices B and D are valid calculations and should have resulted in the same estimate. Choice B, however, is incorrectly rounded, leaving choice D as the better answer.

___

The other answer choices do not result in a number between 5 and 6, so are clearly incorrect.

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What’s the value of x ?
igor_vitrenko [27]

Answer:

x = 127

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 6, thus

sum = 180° × 4 = 720°

Sum the interior angles and equate to 720

x + 120 + 100 + 128 + 133 + 112 = 720, that is

x + 593 = 720 ( subtract 593 from both sides )

x = 127

7 0
3 years ago
K dived by 11 is 7<br> solve for k
Romashka [77]

Answer:

k = 77

Step-by-step explanation:

\frac{k}{11} =7\\\\\rightarrow 11 * 7 = 77\\\rightarrow 77 \div 11 = 7

4 0
2 years ago
Read 2 more answers
Plot the point (3, 2pi/3)​, given in polar​ coordinates, and find other polar coordinates (r, θ )of the point for which the foll
exis [7]

Answer:

(a) (3, -\frac{4\pi}{3})

(b) (-3, \frac{5\pi}{3})

(c)(3, \frac{8\pi}{3})

Step-by-step explanation:

All polar coordinates of point (r, θ ) are

(r,\theta+2n\pi) and (-r,\theta+(2n+1)\pi)

where, θ is in radian and n is an integer.

The given point is (3, \frac{2\pi}{3}). So, all polar coordinates of point are

(3, \frac{2\pi}{3}+2n\pi) and (-3, \frac{2\pi}{3}+(2n+1)\pi)

(a) r>0,-2\pi\leq \theta

Substitute n=-1 in (3, \frac{2\pi}{3}+2n\pi), to find the point for which r>0,-2\pi\leq \theta.

(3, \frac{2\pi}{3}+2(-1)\pi)

(3, -\frac{4\pi}{3})

Therefore, the required point is (3, -\frac{4\pi}{3}).

(b) r

Substitute n=0 in (-3, \frac{2\pi}{3}+(2n+1)\pi), to find the point for which r>0,-2\pi\leq \theta.

(-3, \frac{2\pi}{3}+(2(0)+1)\pi)

(-3, \frac{2\pi}{3}+\pi)

(-3, \frac{5\pi}{3})

Therefore, the required point is (-3, \frac{5\pi}{3}).

(c) r>0,2\pi \leq \theta

Substitute n=1 in (3, \frac{2\pi}{3}+2n\pi), to find the point for which r>0,2\pi \leq \theta.

(3, \frac{2\pi}{3}+2(1)\pi)

(3, \frac{2\pi}{3}+2\pi)

(3, \frac{8\pi}{3})

Therefore, the required point is (3, \frac{8\pi}{3}).

4 0
3 years ago
In the solution of the equation 5 minus 3X equals 2X +9, 3X is added to the equation 1st. Which of the following should be done
sasho [114]
You could do any of those, but I would do Add -9 then the equation is -4=5x then divide everything by 5 then x = -.8

3 0
3 years ago
Read 2 more answers
Slope of (-7,-2) (9,4)
Olenka [21]

Answer:

m= \frac{3}{8}

Step-by-step explanation:

1. Use the slope equation to solve the problem

\frac{y_{2} -y_{1}}{x_{2} -x_{1} }

2. Plug in your values into the equation.

\frac{4-(-2)}{9-(-7)}

3. Simplify the equation.

m= \frac{3}{8}

4 0
3 years ago
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