All categories

3 years ago

The effect of mechanical work on an object is _. (complete the sentence.)

Physics

1 answer:

Advocard [28]3 years ago

8 0

Answer:

Displacement (i.e. change in its final position)

Explanation:

In classical mechanics work is described as the displacement of the body in the direction of the applied force.

<u>Mathematically given as:</u>

$W=F.s\ cos\ \theta$

where:

F = force on the body

s = displacement of the body

θ = angle between the force and direction of displacement

While force, acceleration, velocity can also be the answer for the blank space but the displacement effect is visible during and even after the work has been done, so one can notice the change in position of the object even when the person has not seen the process but just the initial condition of the body.

You might be interested in

The angle between the two force of magnitude 20N and 15N is 60 degrees (20N force being horizontal) determine the resultant in m

BARSIC [14]

A) The resultant force is 30.4 N at $25.3^{\circ}$

B) The resultant force is 18.7 N at $43.9^{\circ}$

Explanation:

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

The two forces are:

$F_1 = 20 N$ at $0^{\circ}$ above x-axis

$F_2 = 15 N$ at $60^{\circ}$ above y-axis

Resolving each force:

$F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N$

$F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N$

So, the components of the resultant are:

$F_x = F_{1x}+F_{2x}=20+7.5 = 27.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude of the resultant is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{27.5^2+13.0^2}=30.4 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{27.5})=25.3^{\circ}$

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

$\theta=180^{\circ}-60^{\circ}=120^{\circ}$

So we have:

$F_{2x}=F_2 cos \theta = (15)(cos 120)=-7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 120)=13.0 N$

So, the components of the resultant this time are:

$F_x = F_{1x}+F_{2x}=20-7.5 = 12.5 N\\F_y = F_{1y}+F_{2y}=0+13.0=13.0 N$

And the magnitude is:

$F=\sqrt{F_x^2+F_y^2}=\sqrt{13.5^2+13.0^2}=18.7 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}$

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

7 0

3 years ago

In the periodic table, the properties repeat in what direction?

pogonyaev

Answer:

Left to right and top to bottom

Explanation:

On the periodic table, the properties repeat from left to right and from top to bottom.

Periodic properties have a pattern from the top to the bottom or down a group or family.

Also, across the period from left to right, they also show a repeating pattern.

Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.

7 0

3 years ago

A 1300 kg car traveling at 35 mph rear-ends a 1000 kg car traveling 25 mph. Just after the collision (but before the driver’s sl

guajiro [1.7K]

Answer

given,

before collision

mass of car A = m_a = 1300 kg

velocity of car A = v_a = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

$P_1 = m_av_a + m_b v_b$

$P_1 = 1300 \times 35+ 1000 \times 25$

$P_1 =70500 Kg.m/s$

final momentum

$P_2 = m_aV_a + m_b V_b$

$P_2 = 1300 \times 30+ 1000 \times 31.5$

$P_2 =70500 Kg.m/s$

here initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

6 0

3 years ago

Define the following:

belka [17]

Define the following:
Potential energy: In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Kinetic energy: In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
Mechanical energy:
Chemical energy: chemical energy, Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic. Reactions that require an input of heat to proceed may store some of that energy as chemical energy in newly formed bonds
Sound energy: In physics, sound energy is a form of energy that can be heard by living things. Only those waves that have a frequency of 16 Hz to 20 kHz are audible to humans. However, this range is an average and will slightly change from individual to individual.
Light energy: Light energy is a kind of kinetic energy with the ability to make types of light visible to human eyes. Light is defined as a form of electromagnetic radiation emitted by hot objects like lasers, bulbs, and the sun. Light contains photons which are minute packets of energy.
Nuclear energy: Nuclear power is the use of nuclear reactions to produce electricity. Nuclear power can be obtained from nuclear fission, nuclear decay and nuclear fusion reactions. Presently, the vast majority of electricity from nuclear power is produced by nuclear fission of uranium and plutonium in nuclear power plants

5 0

2 years ago

Read 2 more answers

Bartek w czasie 2minut przesunął ruchem jednostajnym kamień na odległość 0,5m.Oblicz moc mięśni Bartka jeśli siła oporów wynsiła

Ipatiy [6.2K]

Answer:

Bartek's muscle power = 2.667 W

Moc mięśni Bartka = 2.667 W

Explanation:

English Translation

Bartek within 2 minutes moved the stone

steadily at a distance of 0.5 m. Calculate Bartek's muscle power , if the resistance force was 640N.

The power, P, expended or generated by moving a body to move a velocity, v, against a resistive force, F is given as

P = Fv

P = ?

F = 640 N

v = velocity = (0.5) ÷ (2×60) = 0.00416667 m/s

P = 640 × 0.0041666667 = 2.667 W

In Polish/Po polsku

Moc P, zużyta lub wytworzona przez poruszanie ciałem w celu przemieszczenia prędkości v przeciwko sile oporowej, F jest podawana jako

P = Fv

P = ?

F = 640 N

v = velocity = (0.5) ÷ (2×60) = 0.00416667 m/s

P = 640 × 0.0041666667 = 2.667 W

Hope this Helps!!!

Mam nadzieję że to pomoże!!

4 0

2 years ago