The Chair o

Consider a large truck and a small car driving up a straight steep hill. The truck is moving at 60 miles per hour and the car at

Oksana_A [137]

Answer:

The correct answer is option A.

Explanation:

Force is defined as push or pull on an object with mass due to which change velocity occurs (acceleration).

$Force=Mass\times Acceleration$

$F=ma$

$a=\frac{dv}{dt}[tex][tex]m\times \frac{dv}{dt}[tex]We are given with large truck and small car at constant speed, which means that acceleration zero.[tex]a=\frac{dv}{dt}=0$ if ,v = constant

Net force on the vehilce

F = Normal - Weight

0 = N = W

N = W

So, the force experienced by the object will be due to its mass, and higher the mass more will be the experienced by an object.So, large truck will experience larger net force.

7 0

3 years ago

For a satellite of mass mS in a circular orbit of radius rS around the Earth, determine its kinetic energy, K . Express your ans

agasfer [191]

Since it is asking you to find the kinetic energy in relation to the mass, radius, mechanical energy (total energy), and constants, you will need to setup an equation first to "find" the Mechanical Energy, so that we can then solve for the kinetic energy, as from my experience with high school physics, there is only the graviational potential energy equation and force in relation to celestial bodies.

Knowing the ME is the total energy, we add up the energies of the system. Since it is being influenced by the Earth, as per the problem stating the satellite has circular orbit around the Earth, we know there is gravitational potential. Since it is orbiting, we can assume some type of velocity. Nothing else that we need to worry about should be occuring at this level of physics, leaving you with

ME= Ug+K

from here we solve for K, as plugging in could get confusing and messy at the moment.

ME-Ug=K

now using the equations presumably given in class, if not then using this equation, we can find the Ug

Ug=(-(Gm*M)/r) note that M is the mass of the Earth and m is the satellite

this should give us

ME-(-(GmM)/r)=K

since there is a negative being subracted, we can change that to

ME+(GmM)/r=K

I believe this should be fine, as the Earth's mass is constant, but if not, then all you need to figure left is how to get rid of the M in the equation, as the rest of the terms and constants are for sure within the requirements.

8 0

2 years ago

Which cycle causes earthquake and volcanic activity? carbon water tectonic phosphorus

erik [133]

The answer would be tectonic. hope this helps (:

6 0

3 years ago

Read 2 more answers

A pressure that will support a column of Hg to a height of 256 mm would support a column of water to what height? The density of

Paul [167]

Answer:

The height of water in the column = 348.14 cm

Explanation:

Pressure:This is defined as the ratio of the force acting normally ( perpendicular) to the area of surface in contact. The S.I unit of pressure is N/m²

p = Dgh............... Equation 1

Where p = pressure, D = density, g = acceleration due to gravity, h = height.

From the question, the same pressure will support the column of mercury and water.

p₁ = p₂

Where p₁ = pressure of mercury, p₂ = pressure of water

D₁gh₁ = D₂gh₂.................. Equation 2

making h₂ the subject of equation 2

h₂ = D₁gh/D₂g............... Equation 3

Where D₁ and D₂ = Density of mercury and water respectively, h₁ and h₂ = height of mercury and water respectively

Given: D₁ = 13.6 g/cm³, D₂ = 1.00 g/cm³, h₁ = 256 mm = 25.6 cm.

Constant: g = 9.8 m/s²

Substituting these values into Equation 3,

h₂ = (13.6×9.8×25.6)/1×9.8

h₂ = 348.14 cm

The height of water in the column = 348.14 cm

6 0

2 years ago

Accourding to biopsychologists a temperament ()

Setler [38]

A persons or animals nature, especially as it permanently affects their behavior

8 0

2 years ago