In the vertical jump, an athlete starts from crouch and jumps upward to reach as high as possible. Even the best athletes spend
little more than 1.00s in the air (thier "hang time"). Treat the athlete as a particle and let ymax be his maximum height above the floor. To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax /2 to the time it takes him to go from the floor to that height. You may ignore air resistance.
1 answer:
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Answer:
the position of the wood below the interface of the two liquids is 2.39 cm.
Explanation:
Given;
density of oil, = 926 kg/m³
density of the wood, = 974 kg/m³
density of water, = 1000 kg/m³
height of the wood, h = 3.69 cm
Based on the density of the wood, it will position across the two liquids.
let the position of the wood below the interface of the two liquids = x
Let the wood be in equilibrium position;
Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.
Answer:
0.546
Explanation:
From the given information:
The force on a given current-carrying conductor is:
where the length usually in negative (x) direction can be computed as
Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:
where;
current I = 7.0 A
F = 546 × 10⁻³ T/mT
F = 0.546