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nika2105 [10]
3 years ago
12

Monique purchases a $5,100 dining room set. She can't afford to pay cash, so she uses the installment plan, which requires an 18

% down payment. How much is the down payment?​
Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

$918 is her down payment

Step-by-step explanation:

.18×5100

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Example 5 suppose that f(0) = −8 and f '(x) ≤ 9 for all values of x. how large can f(3) possibly be? solution we are given that
joja [24]

f'(x) exists and is bounded for all x. We're told that f(0)=-8. Consider the interval [0, 3]. The mean value theorem says that there is some c\in(0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}

Since f'(x)\le9, we have

\dfrac{f(3)+8}3\le9\implies f(3)\le19

so 19 is the largest possible value.

6 0
3 years ago
Mrs. Bryant's homeroom students are collecting boxtops. Each student is responsible for collecting 4% of the class's overall goa
galina1969 [7]

Answer:

Each student; 32

Kevin; 12

Step-by-step explanation:

4% of 800 is 32. Each student is responsible for colleting 32 box tops.

The next step is to figure out what 37.5% of the 32 is 12.

Hope that this helps! Have a good day and good luck!

8 0
3 years ago
Cher wraps 40 presents in 2 hours. At that rate, how many presents would she wrap in 15 minutes
gavmur [86]

Answer:

5 presents

Step-by-step explanation:

40 presents in 2 hours

20 presents in 1 hour (divide by 2)

20 presents in 60 minutes ( 1 hour is 60 minutes )

5 presents in 15 minutes ( divide by 4)

6 0
2 years ago
The cost of a jacket increased from $65.00 to $74.10. What is the percentage increase of the cost of the jacket?
Andreas93 [3]

Answer:

14%

Step-by-step explanation:

14% of 65 is 9.1. so 65+9.1= 74.10

5 0
3 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
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