Answer:
240$
Step-by-step explanation:
$200
OCS
$230
$240
$310
ABCDA. $960
ACDBA. $900
ACBDA. $960
=240
Seven days and a half
For you work 8 hours a day
It takes you 6 hours to per each
You wanna make 10
10 by 6 is 60 on 8 = 7.5
Best luck!
Wise
Answer:
4
Step-by-step explanation:
6*(8*2)^2/(6*8^2)=2^2=4
Answer:
Zeroes : 1, 4 and -5.
Potential roots:
.
Step-by-step explanation:
The given equation is

It can be written as

Splitting the middle terms, we get



Splitting the middle terms, we get



Using zero product property, we get



Therefore, the zeroes of the equation are 1, 4 and -5.
According to rational root theorem, the potential root of the polynomial are

Constant = 20
Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.
Leading coefficient= 1
Factors of leading coefficient ±1.
Therefore, the potential root of the polynomial are
.
The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907