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GaryK [48]
3 years ago
15

4x-9y=9

Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0
Multiply both sides of the second equation by 4. That will give you -4x in the second equation which when added to 4x of the first equation will eliminate x.

Second equation:
-x + 3y = 6

Multiply the second equation by 4 on both sides:
-4x + 12y = 26
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X = 5y/(z-4y) <br><br> make y subject
Margarita [4]

Answer:

y=2x/5-4x

Step-by-step explanation:

multiply z-4y on both sides,match the Ys together and then make y common

3 0
2 years ago
Bob's youth group is selling candy bars for a fundraiser. The candy bars cost $2 each. To date, they have raised $700. Their goa
Brilliant_brown [7]
Hey need to sell 1200+ more because if they want more than $3100 and they already have $700 they need $2400 and divide that by 2.
7 0
3 years ago
Read 2 more answers
Jessica is organizing a guided tour of the rain forest. The average profit per person that the touring company makes is given by
Allushta [10]

As a practical equation, this one doesn't make much sense -- why would the profit per person have a term proportional to the number of people?  Let's just go with it.

18x + \dfrac{35}{x}

= \dfrac{18x^2}{x} + \dfrac{35}{x}

= \dfrac{18x^2 + 35}{x}

That's the answer to the first part.

35/x represents a portion of the profit that's 35/x per person, or a constant $35 per tour.

4 0
3 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Convert 9255 cm3 to gallons. Express the volume in gallons to four significant figures.
chubhunter [2.5K]

Answer:

2.44491234

Step-by-step explanation:

1 gallon = 3785 cm3

4 0
3 years ago
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