The formula of a slope:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
We have the points (4, -4) and (k, -1) and the slope m = 34.
Substitute:
![\dfrac{-1-(-4)}{k-4}=34\\\\\dfrac{3}{k-4}=\dfrac{34}{1}\qquad|\text{cross multiply}\\\\34(k-4)=3\qquad|\text{use distributive property}\\\\34k-136=3\qquad|+136\\\\34k=139\qquad|:34\\\\k=\dfrac{139}{34}](https://tex.z-dn.net/?f=%5Cdfrac%7B-1-%28-4%29%7D%7Bk-4%7D%3D34%5C%5C%5C%5C%5Cdfrac%7B3%7D%7Bk-4%7D%3D%5Cdfrac%7B34%7D%7B1%7D%5Cqquad%7C%5Ctext%7Bcross%20multiply%7D%5C%5C%5C%5C34%28k-4%29%3D3%5Cqquad%7C%5Ctext%7Buse%20distributive%20property%7D%5C%5C%5C%5C34k-136%3D3%5Cqquad%7C%2B136%5C%5C%5C%5C34k%3D139%5Cqquad%7C%3A34%5C%5C%5C%5Ck%3D%5Cdfrac%7B139%7D%7B34%7D)
Answer:
Jaime's wrong, becuase the distance(absolute value) from the point estimate to the lower bound is different than he distance from the upper bound to the point estimate.
Step-by-step explanation:
The distance(absolute value) from the point estimate to the lower bound must be the same as the distance from the upper bound to the point estimate.
The point estimate is 0.14.
Jaime
Jaime's interval has a lower bound of 0.049 and an upper bound of 0.191
upper - point = 0.191 - 0.14 = 0.051
point - lower = 0.14 - 0.049 = 0.091
Jaime's wrong, becuase the distance(absolute value) from the point estimate to the lower bound is different than he distance from the upper bound to the point estimate.
Mariya
Just to check.
Mariya's interval has a lower bound of 0.079 and an upper bound of 0.201.
upper - point = 0.201 - 0.14 = 0.061
point - lower = 0.14 - 0.079 = 0.061
Mariya has the same distances, so it is correct.
That is so wrong three dollars is 300 cents
Answer: The link doesnt work :/
Step-by-step explanation:
The equation of the line:
y = m x + c
m is the slope , c is constant
so m = 1/2 (given)
so y = (1/2) x + c
c will be calculated from the given point as y -1 when x =-3
then -1 = (1/2) * -3 + c
c = -1 +(1/2)*3 = 1/2
so y = (1/2) x + (1/2)
the graph of function is as shown in the figure