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Oduvanchick [21]
2 years ago
14

Graph the line of the equation 8x/5 - 2y = -8 using its slope and y-intercept

Mathematics
1 answer:
satela [25.4K]2 years ago
5 0

Answer:

y=\frac{4}{5}x+4

Step-by-step explanation:

You'll need to get this equation in slope-intercept form by solving for y. I do a little extra here to get it in the correct form, but I think it's pretty clear. Let me know if I need to clarify.

\\\\\frac{8x}{5}-2y=-8\\\\-2y=-\frac{8x}{5}-8\\\\2y=\frac{8x}{5}+8\\\\y=\frac{4}{5}x+4

Once it's in slope-intercept form, both the slope and the y-intercept are readily available so you can easily graph it. I graphed both of them in the attached image so you can see that they are the same line.

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Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
Simplify 5 – 2y + (-8y) + 5.5.
zavuch27 [327]

Answer:

-10y + 10.5

Step-by-step explanation:

5 - 2y + (-8y) + 5.5

5 - 2y - 8y +5.5

-10y + 10.5

3 0
2 years ago
Read 2 more answers
Please help ASAP ‼️‼️
Viefleur [7K]

Answer:

what do you need help with?

Step-by-step explanation:


5 0
2 years ago
The box and whisker plots below show two classes' semester grades. Write a paragraph comparing the two sets of
oksano4ka [1.4K]

The paragraph to show the comparision between two classes semester grades on the basis of the terms

  • extremes
  • quartiles
  • medians
  • ranges

is given below:

<h3>What is Box and Whisker plots?</h3>

A box and whisker plot is defined as a graphical method of displaying variation in a set of data.

From the first figure, write all the values where dark point is drawn

53, 62, 80, 86, 89  

  • The lower extreme is the smallest value, which is 53.

        The upper extreme is the highest value, which is 89.

  • The median will be the middle of data , which is 80

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

        The upper quartile is 86 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =89-53

       =36

From the second figure, write all the values where dark point is drawn

56, 62, 74, 89, 96

  • The lower extreme is the smallest value, which is 56.

        The upper extreme is the highest value, which is 96.

  • The median will be the middle of data , which is 74.

  • The upper quartile is the median of the upper region and the lower quartile is the median of the lower region.

       The upper quartile is 89 and the lower quartile is 62.

  • Range of the data be,

       = Highest - Lowest

       =96-62

       =34

From the above discussion,  

  • The First class have less upper extreme value than the second class.
  • The First class have less lower extreme value than the second class.
  • The First class have greater median than the second class.
  • The First class have less upper quartile than the second class.
  • The First and second class have equal lower quartile.
  • The First class have greater range than the second class.

The comparision of the two classes on the basis of extremes, quartile, median, range is concluded above.

learn more about box and whisper plot here:

brainly.com/question/11859288

#SPJ1

6 0
1 year ago
You place a 16 foot ladder against a building. The angle that the ladder forms with
gulaghasi [49]

Answer:The base of the ladder should be placed so that it is one foot away from the building for every four feet of hight to where the ladder rests against the building. This is known as the 4 to 1 rule.

Step-by-step explanation:

7 0
2 years ago
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